I have been folding a lot of the models from Robert J. Langs "the Complete Book of Origami" and I am interested in folding some of the harder models, like the Bassist, Violinist and Pianist. However, I cannot figure out the dimensions for these.
I have already figured out that the Viking Ship with dimensions of 1:4.667 is 1:4 2/3. But I need help with the others. Here are the dimensions:
Why don´t you just multiply the size you want the smaller side to be with the data mentioned and take the next measurable number?
Let´s say I want a violinist with the width of 25 cm, so the height would be 35,35 cm or equally 10" to 14,14".
By the way 1 : 1,414 is approximately A4.
For the pianist Lang describes a method how to get the needed length by beginning with a 1:4 paper and cutting of the exccess after folding a few steps.
Not sure about the bassist, but I know the diagrams showed how to get the rectangle for the pianist from a rectangle longer than 1x3.874 (Such as a 1x4)
I have figured out that 1:1.414 is indeed a silver rectangle. But how do I figure out 1: 2x(1+sqrt(2))? Remember, I know only up to grade nine level math. Would it be 2:2.414?
Edit: I think I've figured it out now. Take a silver rectangle, add a square below it and multiply by two, putting them side by side. That would make the equivalent size paper, wouldn't it?
Heres what I mean:
You could actually do something easier for the bassist. Get an A4 sheet of paper and fold it diagonally like you're cuting a square. Cut of half of the protruding edge and there you have it!
I'm pretty sure i know how to make a 1:1.207 rectangle now. Make a silver rectangle, divide in half horizontally and vertically and make squares touching half in the bottom half (cut off paper from below the squares)